What is the value of k if x^(3)+kx^(2)+7x+5 is divided by x+4 and gives a remainder of -7?

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Step-by-step explanation:

Let p(x)=x³-kx²+11x-6 Since( x-1) is afactors of the given polynomial p(x) then x=1 ... How do I factor "3x^3 + 5x^2 - 3x - 5 = 0" (the answers are "-1, 1, -5/3")? 3,694 Views · If (x+4) and (x-1) are factors of k(x) =x^3+mx^2-nx+8, what is the value of m and n? ... If x-1 is a factor, then division will result in a remainder of 0.

Step-by-step explanation:

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: