If is an isosceles triangle, with base AC, AB = 3x+2, BC = 7x-6, and AC = 10x – 10, find the value of x and the length of each side of the triangle.

Step-by-step explanation:

If is an isosceles triangle, with base AC, AB = 3x+2, BC = 7x-6, and AC = 10x – 10, find the value of x and the length of each side of the triangle.

The sum of angles in a triangle = 180°

AB + BC + AC = 180°

3x + 2 + 7x - 6 + 10x - 10 = 180°

20x -14 = 180°

20x = 180° + 14

20x = 194

step-by-step explanation:

no solution.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)