Can somebody help me with this question, please? I have no idea how to do this or find the answer. :/ How many ways are there to choose a number from the set {−96, −48, −42, −36, −18, −14, −6, 14} that is divisible by either 6 or 8?

28 different ways

Step-by-step explanation:

This is a combination question. Combination has to do with selection.

Total number of element in the set = 8

Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}

Total number divisible by 6 or 8 is 6

The number of ways we can choose 6 items from 8 is expressed as;

8C6 = 8!/(8-6)!6!

8C6 = 8!/(2)!6!

8C6 = 8*7*6!/2!6!

8C6 = 8*7/2

8C6 = 56/2

8C6 = 28 ways

Hence there are 28 different ways

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !