You and your friends are having a race, but since you are faster than he is, you decide to give him a head start. He starts 10 m In front if the starting line, while you start on the starting line. You run at 6 meters/ second, while your friend runs at 5.5 meters/ second. After how many seconds will you and your friend be same distance from the starting line?

the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds

Step-by-step explanation:

The computation of the number of seconds that you and your friend would be have the similar distance from the starting line is shown below:

As we know that

Speed = Distance ÷ Time

SO,

Time = Distance ÷ speed

= 10 meters ÷ difference in speed

= 10 meters ÷ (6 meters per second - 5.5 meters per second)

= 10 meters ÷ 0.5 meters per second

= 20 seconds

hence, the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds

idk

step-by-step explanation:

use that smart brain

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.