Given f(x)=x(x-3)+4 what is the derivative of f at a?

Let g(x) = f'(x)

Substitute a in x, therefore the answer is.

— Note that it'd be better to use f'(a) or y' instead. For this one, I let g(x) equal the derivative of f(x) —

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

7

step-by-step explanation: