PLzzz help meee In rhombus MATH, the coordinates of the endpoints of the diagonal MT are M(0, 2) and T(4, 6). Write an equation of the line that contains diagonal AH. Give your answer in slope-intercept form.

y = - x + 6

Step-by-step explanation:

-- Rhombus diagonals are perpendicular and bisect each other.

-- A( , ) and B( , )

Coordinates of the midpoint of a segment AB are

( , )

and formula of a slope of the line segment AB is

m =

-- If AB ⊥ CD then × = - 1

-- Slope-point of linear equation is

y - = m( x - )

~~~~~~~~~~~~~~~~

M(0, 2)

T(4, 6)

= = 1

= - 1

Coordinates of the intersection of the diagonals are ( , ) = (2, 4)

y - 4 = - 1(x - 2)

y = - x + 6 is slope-intercept form of the diagonal AH

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

answer: .75 km

step-by-step explanation: