What is the largest 4-digit number that is equal to the cube of the sum of its digits?

step-by-step explanation:

just plug in each number for x and see which ones work and don't

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.