Mathematics, 08.12.2020 16:40 arrissa1234hinkle

1+[cosecA. tanB]^2/1+[cosecC. TanB]^2=1+[cotA. SinB]^2/1+[cotC. sinB]^2

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1+[cosecA. tanB]^2/1+[cosecC. TanB]^2=1+[cotA. SinB]^2/1+[cotC. sinB]^2...