Find the equation of the line passing through the point (–1, 0) and parallel to the line y = –1∕2x + 3∕7 Question 4 options:

A)
y = ½x + ½

B)
y = –½x + ½

C)
y = –½x – ½

D)
y = 2x + 2

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

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x:       y:  

-1         4

0         4

1         6

2         18

3         20