Find a polynomial with a degree of 3, and the zeros 1,7, & -4 with no other zeros.

Step-by-step explanation:

zeroes are when you plug in that x value and get y=0

therefore if you set x = that number and solve for 0 you get a "function"

multiplying these together will yield the complete 3rd degree polynomial

x = 1

x-1=0

x=7

x-7=0

x=-4

x+4=0

If needed you could expand but I'm too lazy

found it xd it ok yt

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.