FAST i'll mark you brainliest The coordinates of A are (2 , -9) and the coordinates of G are ( -14 , 3). What are the coordinates of the midpoint of AG ?

(-6, -3) i think

Step-by-step explanation:

(-6,-3)

Step-by-step explanation:

Use the midpoint formula:

M = (x1+x2/2), (y1+y2/2)

Plug in the x's for the first part and y's for the second.

M=-14+2/2 = -12/2 = -6

-9+3/2 = -6/2 = -3

The answer is (-6,-3)

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)