65 POINTS I NEED HELP ASAP PLS I need help on two questions. It's for an assignment but idk what to do, pls help. The assignment is on Absolute Value functions, Equations, and Inequalities. I will mark brainliest to the one to show work, I really want to understand it...Question 1:
Solve,
2|2x-1|-2=12

Question 2:
Solve,
4|x-5|+3>23

part 1;   x=4,−3

part 2: im not sure

x < 0  or  x > 10

Step-by-step explanation:

1. x=-3 or x=4

2. x>10 or x<0

Step-by-step explanation:

1. 2|2x-1|-2=12

2|2x-1|=14

|2x-1|=7

2x-1=±7

2x= -6    2x=8

x=-3    or     x=4

2. 4|x-5|+3>23

4|x-5|>20

x-5>±5

x>10  or   x<0

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.