On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 6), point B is at (negative 1, 1), and point C is at (2, 2). Triangle ABC is an isosceles triangle in which AB = AC. What is the perimeter of △ABC? 5 + StartRoot 10 EndRoot units StartRoot 10 EndRoot units 10 + StartRoot 10 EndRoot units 15 units

10 +√10

Step-by-step explanation:

Given the coordinates of the triangle expressed as

A(-1,6), B(-1, 1) and C(2,2)

The perimeter of the triangle=  AB + BC + AC\

Since AB = AC

P = AC + BC + AC

P = 2AC + BC

get the length AC using the formula;

Given A(-1,6) and C(2,2)

AC = √(2-(-1))²+(2-6)

AC = √3²+4²

AC = √9+16

AC = √25

AC = 5

Get BC

B(-1, 1) and C(2,2)

BC = √(2-(-1))²+(2-1)

BC = √3²+1²

BC = √9+1

BC = √10

Perimeter = 2(5)+√10

Perimeter = 10 + √10

Hence the perimeter of the triangle is 10 +√10

21.4 i did it already for s1

step-by-step explanation:

won't that be plagrisim thought?

step-by-step explanation: