What is the value of AAA when we rewrite 4^{31x}4 31x 4, start superscript, 31, x, end superscript as A^{ x}A x A, start superscript, x, end superscript

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step-by-step explanation:

i think the answer is b

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

i believe the answers 600m