Can someone please help me with this question??

The probability that a randomly chosen child in 11th grade and play tennis is 9.6% ⇒ D

Step-by-step explanation:

The table represents the percentage of the students in each sport

→ The rows represent the grades level, the columns represent the sports

∵ The percentage of students in grade 11 = 40%

∴ The probability of choosing a child in grade 11th = = 0.40

∵ The percentage of students who playing tennis = 24%

∴ The probability of choosing a child who playing tennis = = 0.24

→ We need to find the probability of a randomly chosen child in

   11th grade and playing tennis

∵ The probability of A and B is P(A) . P(B), where P(A) is the probability of

   choosing a child in 11th grade and P(B) is the probability of choosing

   a child playing tennis

∵ P(A) = 0.40 and P(B) = 0.24

∴ P(A) and P(B) = 0.40 × 0.24

∴ P(A) and P(B) = 0.096

→ Change it to a percentage by multiplying it by 100

∴ P(A) and P(B) = 0.096 × 100%

∴ P(A) and P(B) = 9.6%

∴ The probability that a randomly chosen child in 11th grade and

   play tennis is 9.6%

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)