Write an equation in standard form with the points (6,11) and (5,9) on the line

2x - y = 1
explanation:

The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m=y2-y1/x2-x1

with (x₁, y₁ ) = (6, 11) and (x₂, y₂ ) = (5, 9)

m=9-11/5-6= -2/-1= 2

thus
y = 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (5, 9) , then
9 = 10 + c ⇒ c = 9 - 10 = - 1
y = 2x - 1 ← in slope- intercept form
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
From y = 2x - 1 ( subtract y and add 1 to both sides )
2x - y = 1 ← equation in standard form

We need the pictures of the graphs

3x+9+4x+x=8x+9that's the answer for your question.