On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and the y-axis at (0, 0). Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and the y-axis at (0, 0). Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)

Given:

A curved line with a minimum value of (-1,-2), crosses the x-axis at (-2, 0) and the y-axis at (0, 0).

To find:

x-intercepts of the function.

Solution:

The curved line passes through the points (-1,-2), (-2,0) and (0,0).

We know that, y-coordinate is zero at x-intercepts.

From the given points, only (-2,0) and (0,0) have 0 as y-coordinate.

So, x-intercepts of the function are (-2,0) and (0,0).

Therefore, the correct options are 1 and 3.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3