Find three consecutive odd integers such that the difference of thrice the smallest and twice the largest is -19

Answer:

Step-by-step Explanation:

Let the three consecutive odd integers be x, x + 2 and x + 4 because odd integers are in the gap of 2.

GiveN:

This can be written as:

➛ 3(x) - 2(x + 4) = -19

➛ 3x - 2x - 8 = -19

➛ x - 8 = -19

➛ x = -11

Then:

The consecutive odd integers are:

answer: it's upside down and i can't read it

step-by-step explanation: