from 2 cities that are 500 mi apart, 2 cars left simutaneously moving toward each other. The speed of one car is 10 mph greater than the other car. In 5 hours cars met. Find the speed of each car

The speed of one car is 45 miles per hour

The speed of other car is 55 miles per hour

Step-by-step explanation:

Given as :

The distance between the two cities = 500 miles

The Time at which the two cars meets = 5 hours

The speed of one car was 10 mph greater than the speed of other

Now, let the speed of one car = s mph

So, The speed of the other car = ( 10 + s ) mph

According to question both car moving towards each other

So, The relative speed = s +  ( 10 + s )

Since distance = speed × time

Or, 500 miles = [ s +  ( 10 + s ) ] × 5

Or, 500 = ( 10 + 2 s )  × 5

Or, 10 + 2 s =

Or,  10 + 2 s = 100

or, 2 s = 100 - 10

Or, 2 s = 90

∴ s =  

I.e s = 45 mph

So, the speed of one car = s = 45 mph

The speed of other car = 10 + s = 10 + 45 = 55 mph

Hence The speed of one car is 45 miles per hour

And The speed of other car is 55 miles per hour  Answer

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Step-by-step explanation:

arithmetic sequence: a sequnce in which the diffrence between any two consecutive terms is the same

step-by-step explanation: