If a box is 4 feet long by 3 feet wide, how wide of a picture frame could be put inside it of it diagonally?
8
5
7
4

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

angle efh= angle egh

df =

both have same length