What is the best substitution to make to evaluate the integral of the product of 4 minus x and 5 raised to the 4 minus x quantity squared, dx ? here I've stated it differently(it's the same integral): integral (4-x)5^(4-x)^2 dx
Answers:
u = 4 - x
u = (4 - x)2
u = 5(4 - x)
u = -x

i pretty sure it is

idk lol xd

step-by-step explanation:

ez do it yourself lazy

my answer got deleted but it's a

step-by-step explanation:

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -