A race car accelerates uniformly from 18.5 m/s to 50.5 mys in 2.45 seconds. Determine the acceleration of the car.

79.78 m.

Step-by-step explanation:

The acceleration is 11.17 m/s^2.

The distance traveled is 79.78 m.

Acceleration is change of velocity over time. The change of velocity is from 18.5 to 46.1 m/s or 46.1 - 18.5 = 27.6 m/s. The time of change is 2.47 s. So the acceleration is 27.6 m/s / 2.47 s = 11.17 m/s^2.

The distance traveled is average velocity times time of travel. Average velocity is 1/2 of the change of velocity added to the initial velocity, or 1/2•[final velocity (46.1 m/s) - initial velocity (18.5 /s)] + 18.5 m/s or 1/2•27.6 m/s + 18.5 m/s = 32.3 m/s. The time of travel is 2.47 s. So the distance traveled is average velocity 32.3 m/s times 2.47 s = 79.78 m.

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads

idk man good luck man