The function h(0) = -16t2 + vt + 10 gives the height of a platform diver above the water, in feet, t seconds after the diver leaves the platform with an initial velocity, v, in feet per second.
10 feet
On one dive, it takes the diver 1.42 seconds to reach the surface of the water.
• What was the initial velocity, V, in feet per second of the diver?
• After how much time, in seconds, since leaving the platform did the diver reach the same height as the platform?
What was the diver's maximum height, in feet, above the water?

send it over

step-by-step explanation:

a and c

step-by-step explanation:

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm