You purchased concentrated cleaner that must be diluted (watered down) before use. Container A is the cleaner, which is a 20% solution. Container B is pure water. You are mixing together the contents of Container A and Container B to produce 40 gallons of 9% solution. How many gallons from each container are needed to create the 40 gallons of 9% cleaning solution? Write your answers as integers only. Container A: 20% Cleaning Solution =

gallons

Container B: Pure Water =

gallons

Amount of chemical solution = 18 gallon

Amount of pure water = 22 gallon

Step-by-step explanation:

Assume;

20% of solution = x

So,

Amount of pure water = 40 gallons - x

Amount of pure water = 40 - x

Computation:

20% of x = 9% of 40 gallon

0.2 x = 3.6

x = 3.6 / 0.2

x = 18 gallon

So,

Amount of chemical solution = 18 gallon

Amount of pure water = Total solution - Amount of chemical solution

Amount of pure water = 40 -18

Amount of pure water = 22 gallon

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

i do not know the answer

step-by-step explanation: