PLEASE HURRY WILL GIVE BRAINLIEST if you show your work!

(x² + 7x + 6) ÷ (x² + 2x + 1)

This should be in the form of a fraction, I just don't know how to format it that way on here.

Step-by-step explanation:

Since your denominators are equal on both fractions, you just need to subtract your numerators.

3x² + 9x + 12 - (2x² + 2x + 6)

When there is a - in front of an expression in parenthesis, you should change the sign of each term in the expression of the numerator being subtracted.

So this:

2x² + 2x + 6

Will become this:

2x² - 2x - 6

This is how it will look:

3x² + 9x + 12 - 2x² - 2x - 6

Now all you have to do is collect the like terms.

3x² and -2x² are like terms so you will add them together: 3x² + (-2x²) = 3x² - 2x² = x²

This is how your numerator should look so far:

x² + 9x + 12 - 2x - 6

Now we move on to the next like terms.

9x and -2x are like terms so we add them together: 9x + (-2x) = 9x - 2x = 7x

This is how your numerator should look so far:

x² + 7x + 12 - 6

Now we move on to the last set of like terms.

12 and -6 are like terms so we add them together: 12 + (-6) = 12 - 6 = 6

This is how your numerator should be now:

x² + 7x + 6

Now all you have to do is put your numerator on top of your denominator which is the same as in the start of your equation (x² + 2x + 1).

You are done! I hope this was clear and you understand :)

answer: idk

step-by-step explanation:

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: