What is the conjugate? See image below! Please help asap 1) 4- sqrt(7)
2) 8+ sqrt (-5)

Sqrt is square root, use the answers listed to the right

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Step-by-step explanation:

The conjugate is found by changing the sign of the square root term.‡ (For this purpose, i = √-1.)

a) the sign of 3i is changed: 2 + 3i

b) the sign of sqrt(-5) is changed: 8 -sqrt(-5) = 8 -i√5

c) the sign of 2i is changed: 7 +2i

d) the sign of sqrt(7) is changed: 4 +√7

‡ Actually, the conjugate of a binomial is formed by changing the sign between terms. The purpose is to allow the product of the binomial and its conjugate to be the difference of squares.

Conventionally, the conjugate of a complex number is the value with the sign of the imaginary part reversed. That is why (-2i+7)* = 7+2i.

answer: need picture of problem

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.