The sum of the digits of a two digit number is 9 When the digits are reversed the number increases by 9. Find the number.

45

Step-by-step explanation:

Let the unit place be ‘x'

Tenth place be y

The number is 10y+x

x+y = 9 (according to the condition) (1)

Digits are interchanged Unit place' y ‘& tenth place ‘ x'

New no is 10x +y

This is 9 more than the original number

10x+ y = 10y+x +9

10x-x+y-10y = 9

9x-9y= 9

x-y = 1 (dividing by 9) (2)

Adding the two equations

2x = 10

x= 5

Substituting the value of x in first equation

y = 4

The number is 45, the original number is 54 this is 9 more of the new number.

Ans :45

1,8,15,22,29,36,43,50

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.