How do you solve the trinomial 2x^2-19xy+24y^2

Step-by-step explanation:

2x^2- 19xy+ 24y^2

24y^2+ 2x^2-19xy

put them in order by the lowering of the exponent. it is unable to be simplified

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

the answer is simply just 6n add the two together as they have an n