Mathematics, 04.12.2020 01:20 elmo4851
Let sin(2x)-sin(x)=0,where 0<x<2pi. what are the possible solutions for x?
a. {pi/6,5pi/6}
b. {pi/3, 5pi/3}
c. {pi/6,pi/2,5pi/6,3pi/2}
d. {0,pi/3,pi,5pi/3}
Answers: 3
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Let sin(2x)-sin(x)=0,where 0<x<2pi. what are the possible solutions for x?
a. {pi/6,5pi/6}
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