Solve the initial value problem. dy
= csc(x), y(1) = -6
dx
Select one:
O a. y = {x'csc (t) dt – 6
O b. none of these
O c. y = | csc (t) dt + 1
O d. y = ls' -csc (t) dt – 6
O e. y = Jcsc (1) dt – 6

0 is its x and y coordinate

a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!