4cos^2(x)-7cos(x)+3
Please help and explain how you did it :)

I assume you're asked to solve

4 cos²(x) - 7 cos(x) + 3 = 0

Factor the left side:

(4 cos(x) - 3) (cos(x) - 1) = 0

Then either

4 cos(x) - 3 = 0   or   cos(x) - 1 = 0

cos(x) = 3/4   or   cos(x) = 1

From the first case, we get

x = cos⁻¹(3/4) + 2nπ  or   x = -cos⁻¹(3/4) + 2nπ

and from the second,

x = nπ

where n is any integer.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!