What is an equation of the line that passes through the point (-3,1) and is parallel to the line 4x + 3y = 15?

Step-by-step explanation:

Hey there!

The given point is; (-3,1) and another equation is 4x + 3y = 15.

Let's use one point formula and find out the equation of the line which passes through the point.

Keep all values.

Let it be equation (i)

And another equation 4x + 3y = 15.........(ii)

Now, from eqaution (ii)

Put all values.

As per the condition of parallel lines; m1 = m2.

As per the condition of parallel lines; m1 = m2.Therefore, m1= m2= -4/3.

Now, keeping the value of slope (m1) on eqaution (i).

Simplify it.

Therefore, the eqaution is 4x+3y-9=0.

Hope it helps...

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)