A farmer has 300 feet of fence available to enclose a 4500 square foot region in the

shape of adjoining squares, with sides of

length x and y. The big square has sides of

length x and the small square has sides of

length y. Find x and y.

LTTUUL

x= ? feet

y = ? feet

Given :

A farmer has 300 feet of fence available to  enclose a 4500 square foot region in the  shape of adjoining squares, with sides of  length x and y.

The big square has sides of  length x and the small square has sides of   length y.

To Find :

The value of x and y.

Solution :

From attached figure perimeter is given by :

x + x + x + y + y + y + ( x-y ) = 300 ft

4x + 2y = 300

2x + y = 150  ...1)

Now, area is given by :

A = x² + y²

x² + y² = 4500  ...2)

Putting value of y in equation 2), we get :

y = 150 - ( 2× 60 )

y = 30 ft

Therefore, the value of x and y is 60 ft and 30 ft respectively.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

42.4

step-by-step explanation:

convert to decimal