Bill spent less than $36 on Kitten and puppy magazines kitten magazines cost $4 each and puppy magazines cost $3 each A) write an inequality that describes the situation B) list two possible combinations of puppy and kitten magazines C) if bill bout 3 kitten magazines, how many puppy magazines can he buy?

A) 4k + 3p < 36

B) 3 kitten magazines and 4 puppy magazines

4 kitten magazines and 6 puppy magazines

C) If bill bought 3 kitten magazines, then he buys less than 8 puppy magazines.

Step-by-step explanation:

Let:

The number of kitten magazines = k

The number of puppy magazines = p

A) Write an inequality that describes the situation

We are told:

Bill spent less than $36 on Kitten and puppy magazines kitten magazines cost $4 each and puppy magazines cost $3 each

Hence:

$4 × k + $3 × p < 36

4k + 3p < 36

B) List two possible combinations of puppy and kitten magazines

4k + 3p < 36

Bill can buy:

3 kitten magazines and 4 puppy magazines

4 kitten magazines and 6 puppy magazines

C) If bill bought 3 kitten magazines, how many puppy magazines can he buy?

Using the inequality above:

4k + 3p < 36

4k + 3p < 36

4 × 3 + 3p < 36

12 + 3p < 36

3p < 36 - 12

3p < 24

p < 24/3

p < 8

If bill bought 3 kitten magazines, then he buys less than 8 puppy magazines.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!