In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3} 3 1 of an hour. His swimming partner, Mila, swam \frac {2}{3} 3 2 of Logan's distance in \frac {1}{4} 4 1 of an hour. what is milas average speed

2 km/hr

Step-by-step explanation:

Distance traveled by Logan = 750 m = 0.75 km =

Time taken by Logan =

To calculate the speed using time and distance, following formula is used:

Speed of Logan :

Distance traveled by Mila = of Logan's distance:

Time taken by Mila =

As per formula above:

Average Speed of Mila is given as:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?