Three students Tahat, Promi and Kabi, Appeared at an examination. Promi secured 11 marks less than Tahat, 5 marks more than kabi and again. Tahat's marks were 75% of the sum of Promi and Kabi's marks. Find out their individual marks

    Tahat= 40.5 marks    Promi =29.5 marks,  Kabi =24.5 marks

Step-by-step explanation:

Step 1

Let the marks be represented as  x+11, x and x-5 for Tahat, Promi and Kabi respectively

and Tahat's marks which was 75% of the sum of Promi and Kabi's marks be expressed as

x+11 = 75/100(x + x-5)  

Step 2 --- Solving

x+11 = 75/100(x + x-5)  

x+ 11 = 3/4(2x-5)

x+11= 6x-15/4

4x+44=6x-15

44+15=2x

x= 59/2= 29.5,

A) x= Promi's  mark was 29.5

B)Promi secured 5 marks more than kabi

Therefore, Kabi's mark was 5 marks less than Promi

= x-5

29.5- 5= 24.5 marks

C)Promi secured 11 marks less than Tahat, Therefore Tahat marks were 11 marks more than Promi

x+11= 29.5 + 11= 40.5

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step-by-step explanation:

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).