Find the equation of a line that passes through (1,12) and is parallel to the graph of y=3x+3 Write the equation in slope-intercept form, if possible.

The equation of the parallel line is

y = 3x + 9

Step-by-step explanation:

The general equation of a straight line is given as;

y = mx + c

where m is the slope and c is the intercept

If two lines are parallel, their slopes are equal

So the slope of the new line too is 3

Using the point-slope formula

y-y1 = m(x-x1)

y-12 = 3(x-1)

y-12 = 3x-3

y = 3x-3 + 12

y = 3x + 9

i will pick c put check it over to be sure

step-by-step explanation:

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for