Factorise completely a) ( 2 + 2 + 2) a) 9a(x – 3b ) - 4 (x – 3b)
b) 5a(2b – 3 ) - 4 (2b – 3)
c) x( 2h-k )+ 3y ( k – 2h )

a) (9a-4)(x-3b)

b) (5a-4)(2b-3)

c) (x-3y)(2h-k)

Step-by-step explanation:

9a(x – 3b ) - 4 (x – 3b) = (9a-4)(x-3b)

Since both 9a and -4 are multiplied by (x-3b), they can be put in a bracket too.

5a(2b – 3 ) - 4 (2b – 3) = (5a-4)(2b-3)

Since both 5a and -4 are multiplied by (2b-3), they can be put in a bracket too.

x( 2h-k )+ 3y ( k – 2h ) = x(2h-k) - 3y (-k + 2h)

We can multiply + 3y ( k – 2h ) by (-1) to switch up the arithmetic operations.

x(2h-k) - 3y (-k + 2h) = x(2h-k) -3y(2h-k)

Since both x and -3y are multiplied by (2h-k), they can be put in a bracket too.

x(2h-k) -3y(2h-k) = (x-3y)(2h-k)

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

step-by-step explanation: