What is the sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 express your answer as an improper fraction.

Sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is

Step-by-step explanation:

We need to find sum of the first five terms of the geometric sequence in which a1=5 and r=1/5

The formula used to find sum of the geometric sequence is:

Where a is the first term, r is the common ratio and n is the number of terms

Now finding sum of the first five terms of the geometric sequence

We have a=5, r=1/5 and n=5

Putting values in the formula:

So, sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is

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5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116