What is the x and y intercept of the parabola y=x^2-6x+10 and ow do you graph the equation

The x- intercept is where y = 0 on the graph and the y- intercept is where x= 0 on the graph. When X=0, all the terms, except for the constant are equal to zero, thus the y- intercept is the constant. y=10 when x=0. Use the quadratic formula to find the x value where y=0. 
x= (-b +or- sqrt(b^2 -4ac))/2a

y=ax^2 +bx +c

The answer for the x- int is imaginary. This happens because 10 is the parabola's minimum value and it never touches the x- axis. y-int is 10

It says in the questions that it is 6.5?