Find the Maclaurin polynomials p0, p1, p2 for e^−x sin x

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3

simplifying

7ln(x + 2.8) = 11.2

reorder the terms:

7ln(2.8 + x) = 11.2

(2.8 * 7ln + x * 7ln) = 11.2

(19.6ln + 7lnx) = 11.2

solving

19.6ln + 7lnx = 11.2

solving for variable 'l'.

move all terms containing l to the left, all other terms to the right.

reorder the terms:

-11.2 + 19.6ln + 7lnx = 11.2 + -11.2

combine like terms: 11.2 + -11.2 = 0.0

-11.2 + 19.6ln + 7lnx = 0.0

the solution to this equation could not be determined.

step-by-step explanation:

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