how much of an 18% salt water mixture should be added to a 15 gallon 2% salt water mixture to achieve a 7% salt water mixture?

If you add x gal of the 18% mixture, each gallon adds 0.18 gal of salt, so x gal would add 0.18x gal of salt.

The 15 gal of 2% salt mixture already contains 0.02 (15 gal) = 0.3 gal of salt.

The total volume of the new mixture would be (15 + x) gal. To achieve a 7% concentration of salt, you would need to add x gal of the 18% mixture such that

(amount of salt) / (total volume) = (0.3 + 0.18x) / (15 + x) = 0.07

Solve for x :

0.3 + 0.18x = 0.07 (15 + x)

0.3 + 0.18x = 1.05 + 0.07x

0.11x = 0.75

x = 0.75 / 0.11 ≈ 6.82 gal

21

jk it's 20

step-by-step explanation:

38 was the other number of your question.