The vertices of are F(2,1), G(4,1), and H(4,-1). The vertices of the image of the triangle after a dilation centered at (0,0) are F'(4,2), G'(8,2), and H'(8,-2). What is the scale factor of the dilation?

The scale factor of the dilation is 2

Step-by-step explanation:

The given vertices the ΔFGH are;

F(2, 1), G(4, 1), and H(4, -1)

The lengths of the sides of the triangle ΔFGH are;

The length of segment FG = √((4 - 2)² + (1 - 1)²) = 2

The length of segment FH = √((4 - 2)² + ((-1) - 1)²) = 2·√2

The length of segment GH = √((4 - 4)² + ((-1) - 1)²) = 2

After a dilation with the center of dilation = (0, 0), to give the ΔF'G'H', we have;

The given vertices the ΔF'G'H' are F'(4, 2), G'(8, 2), H'(8, -2)

The length of segment F'G' = √((8 - 4)² + (2 - 2)²) = 4

The length of segment F'H' = √((8 - 4)² + ((-2) - 2)²) = 4·√2

The length of segment G'H' = √((8 - 8)² + ((-2) - 2)²) = 4

The length of the sides of ΔFGH = 1/2 × The length of the sides of ΔF'G'H' or the length of the sides of ΔF'G'H' = 2 × The length of the sides of ΔFGH

Therefore, the scale factor of the dilation is 2.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2