I will give and 15 points Question 5 (1 point)
Use the limit process to find the area of the region between the graph of the function y=16-x^2
and x-axis over the interval (-4,4].

The function  will be continuous on the open interval (-4,4) if there is no vertical asymptote or hole on (-4,4).

But the given function has a vertical asymptote at .

Therefore  is not continuous on the interval (-4,4) because x=0 belongs to the given interval.

Step-by-step explanation:

i hope this is right :)

sorry, i can't understand your question. will later if you describe more clearly!

: )