A rabbit moves n times as fast as a squirrel . A fox moves m times as fast as a rabbit . The fox moves how many times as fast as the squirrel?

the fox moves mn times as fast as the squirrel

Step-by-step explanation:

the easiest way to do problems like this is by using hypothetical values that make sense (it's best to avoid 0, 1, and 2)

we'll say that n = 3 and m = 4

so if the squirrel moves at s pace, then the rabbit moves at ns, or 3s.

if the fox moves at m (4) times the rabbit's pace (3s), then it moves at 4(3s)

then just switch out the numbers for their variables, giving you m(ns)

remember that s simply represents the squirrel's pace, we cannot replace it with a number in this case, so switch it with the idea/value it represents

and there you go, mn times the squirrel's pace

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.