In a class of 65 students, 10 students liked Maths but not English and 20 students liked English but not Maths. If 5 students did not like both, how many students liked both subjects?

30 students liked both.

step-by-step explanation: If there are 65 students and 10 liked math but not english you subtract 10 from 65, you get 55. You continue to the next one, 55-20= 35, now there are 35 students but 5 of those students don't like either, so 35-5=30, meaning there are 30 students that like both english and math. I hope this helps.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

y > 1/3x

y < = -x + 4

hope this : )