If one of the zeroes of the cubic polynomial p(x)=ax³+bx²+cx+d is zero then find the product of other two zeroes of p(x).

As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.

Since x is a factor , d= 0

ax^3+bx^2+cx+d = ax^3+bx^2+cx

= x(ax^2+bx+c)

Other two roots are roots of

ax^2+bx+c = 0

For a quadratic equation ax^2+bx+c = 0

Product of roots = c/a

Sum of roots = -b/a

So

Product of other two roots = c/a

Hope this helps :D

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.

i want to die

what the hell man, i just want the points lol