footpath is to be constructed in a park in the shape of a parallelogram. When a coordinate plane is laid over a map of the park, the vertices of the footpath are (−4, 2), (8, 2), (11, 7), and (−1, 7).

Step-by-step explanation:

Step one

Given the coordinates

ABCD with vertices A(−4, 2), B(8,2), C(11, 7), and D(-1, 7).

AB=(−4, 2), (8,2)

BC=(8,2), (11, 7)

CD=(11, 7),(-1, 7)

DA=(-1, 7),(-4,2)

The distance between points AB=

The distance between points BC=

The distance between points CD

The distance between points DA

Hence the perimeter of the footpath= 12+5.8+12+5.8

=35.7

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m