An average scanned image occupies 0.5 megabytes of memory with a standard deviation of 0.2 megabytes. If you plan to publish 80 images on your web site, what is the probability that their total size is between 49 megabytes and 53 megabytes?

Approximately (that's approximately .)

Step-by-step explanation:

The question did not specify the exact distribution of the size of those images. However, the sample size is a rather large number. Assume that:

If both assumptions are met, the central limit theorem would apply. This theorem would suggest that the sum of the sizes of these image (a random variable) will approximately follow a normal distribution. The mean of that sum would be approximately . The standard deviation of that sum would be approximately .

Let denote the sum of these eighty sizes.

Under these assumption, .

That is: .

The question is asking for the probability . Therefore, calculate the -score that corresponding to and :

Make use of a -table to find these two probabilities:

Calculate the probability that this question is asking for:

.

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}