HELP ME ASAP PLS tommy had 8 times more money than loren. when parents gived 35cents to loren and tommy spent 14cents both of kids had same money. how much tommy had in start? how much loren had in start?

Tommy had 56 cents in start and Loren had 7 cents in start.

Step-by-step explanation:

Let,

x be the money Tommy have.

y be the money Loren have.

According to given statement;

Tommy had 8 times more money than Loren.

x = 8y     Eqn 1

Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore

x-14=y+35    Eqn 2

Putting x=8y in Eqn 2

Dividing both sides by 7

Putting y=7 in Eqn 1

Hence,

Tommy had 56 cents in start and Loren had 7 cents in start.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

the answer is 48m^2!

step-by-step explanation: